WebJan 31, 2024 · Alteryx Alumni (Retired) 01-31-2024 01:55 PM You can create a new field in a Formula tool with the expression... DateTimeParse ( [YourDateField], "%A") ...which gives you the day of the week. Then just filter on "Saturday". You can check out all of the Date Specifiers in Help. Reply 0 4 Share rwood330 7 - Meteor 01-31-2024 02:06 PM Thanks … WebJul 2, 2024 · Per documentation, %H is hour in 24 hour clock and %k is 24 hours, leading zero is space. I get null values when trying to format a string to datetime object using %k. 07-02-2024 04:58 PM. today's date is 2024-07-02 in Alteryx. %H is hours (16 - where I am.). %k is currently 16 - but 12 hours ago - it was 4 - %H was 04.
Solved: How convert Timestamp to Datetime - Alteryx …
WebNov 29, 2024 · Go to the Specify Your DateTime Language section below for a list of formats per language. Select the format for the new column: Select the format for your new column from the list, or select Custom to create your own format via the Specify a custom format for the new column field. Refer to the Custom Format section below. WebMar 31, 2024 · Even children know. Users are too busy solving to be bothered with the kindergarten of data which includes date & time handling, adding or eliminating leading zeros in all sorts of numbers, and converting between number & string. These are absurdities we shouldn't have to deal with anymore in our daily work. flow artistic designs
Solved: Convert Text "date/time am pm" to date/time am pm ... - Alteryx …
WebJun 13, 2024 · Version used in Alteryx 10.6. But the type is excel for date shows as number and the user is unable to see the Year/Month/Day hierarchy while applying filter on excel columns. Any suggestions on how to change the format to date would helpful. Thank you. Designer Integration Reply 0 0 Share All forum topics Previous Next 1 REPLY jstarling82 WebFeb 16, 2024 · In this example, the Message function is used within a conditional expression to output a field conversion error message and update column data with a value of "False" if given date-time values do not contain valid time data. If [Hour] = "0" and [Minutes] = "0" then Message(5, "Invalid time in DateTime", "False") Else "True" Endif NULL WebFeb 19, 2024 · The DateTimeDiff calculation only allows for one of the options, either years or months. I assume there is a way to calculate this, but i cant seem to wrap my head around it. (DateTimeDiff ( [GroupTermDate], [GroupMedicalEnrollDate],"Years") Thanks ahead of time Date Time Developer Reply 0 0 Solved! Go to Solution. All forum topics … greek cross architectural plan