In an ap the pth term is q
WebApr 8, 2024 · The qth term is ${T_q} = b = A + (q - 1)D = (A - D) + qD\;\; \to (2)$ The rth term is${T_r} = c = A + (r - 1)D = (A - D) + rD\;\; \to (3)$ Here we have got two unknowns A and D which are to be eliminated. We multiply (1), (2) and (3) by q – r, r – p and p – q respectively and add them together. $$ \Rightarrow a(q - r) + b(r - p) + c(p - q)$$ WebApr 7, 2024 · a + ( p − 1) ⋅ ( − 1) = q ⇒ a − p + 1 = q ∴ a = p + q − 1. Hence, the first term of this arithmetic progression is (p + q – 1). Thus, in order to get the nth term of the AP, we simply need to put the values of the first term and common difference of …
In an ap the pth term is q
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WebJan 3, 2024 · In an AP, the pth term is q and ( p +q) term is 0. Then, prove that its qth term is p. WebJan 14, 2024 · Best answer Solution: Given pth term = 1/q That is ap = a + (p - 1)d = 1/q aq + (pq - q)d = 1 --- (1) Similarly, we get ap + (pq - p)d = 1 --- (2) From (1) and (2), we get aq + (pq - q)d = ap + (pq - p)d aq - ap = d [pq - p - pq + q] a (q - p) = d (q - p) Therefore, a = d Equation (1) becomes, dq + pqd - dq = 1 d = 1/pq Hence a = 1/pq
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WebJul 26, 2024 · Best answer Given: pth term is q and (p + q)th term is 0. To prove: qth term is p. pth term is given by q = a + (p - 1) × d……equation1 (p + q)th term is given by 0 = a + (p + q - 1) × d 0 = a + (p - 1) × d + q × d Using equation1 0 = q + q × d d = - 1 Put in equation1 we get a = q + p - 1 qth term is q + p - 1 + (q - 1) × ( - 1) p Hence proved. WebIf the p t h term of an AP is q and the q t h term is p, prove that its n t h term is ( p + q - n). Solution Step 1: Calculate the common difference. Given: p t h term = q and q t h term = p An AP or arithmetic progression is a sequence of numbers with a common difference between two consecutive numbers.
WebOct 19, 2024 · Class 10 Maths MCQs Chapter 5 Arithmetic Progressions 1. The n th term of an A.P. is given by a n = 3 + 4n. The common difference is (a) 7 (b) 3 (c) 4 (d) 1 Answer/Explanation 2. If p, q, r and s are in A.P. then r – q is (a) s – p (b) s – q (c) s – r (d) none of these Answer/Explanation 3.
WebIf in an A.P., the pth term is q and (p + q)th term is zero, then the qth term is (a) - p (b) p (c) p + q (d) p - q Q. If in an A.P., the pth term is q and (p + q)th term is zero, then the qth term is Q. The pth term of an A.P. is a and qth term is b. Prove that sum of its (p+q) terms is p+q 2 [a+b+ a−b p−q]. Q. how do i change picture on iphoneWebFeb 10, 2024 · In an A.P., if pth term is 1/q and qth term is 1/p, prove that the sum of first pq terms is ½ (pq +1), where p ≠ q. sequences and series class-11 1 Answer +1 vote answered Feb 10, 2024 by sameer (54.7k points) selected Feb 13, 2024 by sanjeev Best answer how much is mot per tonWebOct 29, 2024 · pth term of an AP = q qth term = p Prove: nth term of A.P. is (p+q-n). Proof: We know that, nth term of an AP (an) = a + (n - 1)d Hence, a + (p - 1)d = q a + pd - d = q a = q - pd + d -- equation (1) Similarly, a + (q - 1)d = p Substitute the value of a from equation (1). q - pd + d + qd - d = p qd - pd = p - q - d(p - q) = p - q - d = 1 how do i change plans on huluWebMar 1, 2024 · If the pth Term of an AP is q and qth Term is p. Prove that its nth Term is (p+q-n) Math Army 117K subscribers 18K views 3 years ago If the pth Term of an AP is q and qth... how much is mot in ukWebApr 2, 2024 · View solution. Question Text. BELAKU - Question Bank 2) If the pth term of an AP be q and its qth term be p, then show that the sum of it (p+q)th terms is 21. . how much is mothers allowance in ontarioWebSep 29, 2024 · Click here 👆 to get an answer to your question ️ the pth term of an AP is q and qth term is p. find its (p+q)th term. hardeechoudhary ... Secondary School answered • expert verified The pth term of an AP is q and qth term is p. find its (p+q)th term. See answers how can i mark beacaise only one solution had came yet bacause* ... how do i change powerpoint slide templateWebMar 30, 2024 · Transcript. Example 21 If pth, qth, rth and sth terms of an A.P. are in G.P, then show that (p – q), (q – r), (r – s) are also in G.P. We know that the nth term of AP is a + (n – 1)d i.e. an = a + (n – 1)d It is given that ap, aq, ar & as in GP i.e. their common ratio is same So,𝑎_𝑞/𝑎_𝑝 = (ar )/qq = 𝑎𝑠/𝑎𝑟 We need to show (p – q), (q – r), (r – s) are in ... how much is motivosity